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3 and 4 .Determinants and Matrices
easy
$\left| {\,\begin{array}{*{20}{c}}{a - b}&{b - c}&{c - a}\\{x - y}&{y - z}&{z - x}\\{p - q}&{q - r}&{r - p}\end{array}\,} \right| = $
A
$a(x + y + z) + b(p + q + r) + c$
B
$0$
C
$abc + xyz + pqr$
D
None of these
Solution
(b) $\left| {\,\begin{array}{*{20}{c}}
{a – b}&{b – c}&{c – a}\\
{x – y}&{y – z}&{z – x}\\
{p – q}&{q – r}&{r – p}
\end{array}\,} \right| = \left| {\,\begin{array}{*{20}{c}}
0&{b – c}&{c – a}\\
0&{y – z}&{z – x}\\
0&{q – r}&{r – p}
\end{array}\,} \right| = 0$
$[by {C_1} \to {C_1} + {C_2} + {C_3}]$
Standard 12
Mathematics
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