3 and 4 .Determinants and Matrices
easy

$\left| {\,\begin{array}{*{20}{c}}{a - b}&{b - c}&{c - a}\\{x - y}&{y - z}&{z - x}\\{p - q}&{q - r}&{r - p}\end{array}\,} \right| = $

A

$a(x + y + z) + b(p + q + r) + c$

B

$0$

C

$abc + xyz + pqr$

D

None of these

Solution

(b)  $\left| {\,\begin{array}{*{20}{c}}
{a – b}&{b – c}&{c – a}\\
{x – y}&{y – z}&{z – x}\\
{p – q}&{q – r}&{r – p}
\end{array}\,} \right| = \left| {\,\begin{array}{*{20}{c}}
0&{b – c}&{c – a}\\
0&{y – z}&{z – x}\\
0&{q – r}&{r – p}
\end{array}\,} \right| = 0$

$[by {C_1} \to {C_1} + {C_2} + {C_3}]$

Standard 12
Mathematics

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