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3 and 4 .Determinants and Matrices
easy
$\left| {\,\begin{array}{*{20}{c}}{a - b}&{b - c}&{c - a}\\{x - y}&{y - z}&{z - x}\\{p - q}&{q - r}&{r - p}\end{array}\,} \right| = $
A
$a(x + y + z) + b(p + q + r) + c$
B
$0$
C
$abc + xyz + pqr$
D
इनमें से कोई नहीं
Solution
(b) $\left| {\,\begin{array}{*{20}{c}} {a – b}&{b – c}&{c – a}\\ {x – y}&{y – z}&{z – x}\\ {p – q}&{q – r}&{r – p} \end{array}\,} \right| = \left| {\,\begin{array}{*{20}{c}} 0&{b – c}&{c – a}\\ 0&{y – z}&{z – x}\\ 0&{q – r}&{r – p} \end{array}\,} \right| = 0$
$[{C_1} \to {C_1} + {C_2} + {C_3}$ के द्वारा ]
Standard 12
Mathematics
