- Home
- Standard 12
- Mathematics
3 and 4 .Determinants and Matrices
medium
$\Delta = \left| {\,\begin{array}{*{20}{c}}a&{a + b}&{a + b + c}\\{3a}&{4a + 3b}&{5a + 4b + 3c}\\{6a}&{9a + 6b}&{11a + 9b + 6c}\end{array}\,} \right|$ કે જ્યાં $a = i,b = \omega ,c = {\omega ^2}$, તો $\Delta $ મેળવો.
A
$i$
B
$ - {\omega ^2}$
C
$\omega $
D
$ - i$
Solution
(a) We first operating ${R_3} – 2{R_2}$ and ${R_2} – 3{R_1}$ in given determinant, then we get
$ = a[{a^2} + ab – 2{a^2} – ab] = – {a^3} = i$.
Standard 12
Mathematics