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3 and 4 .Determinants and Matrices
easy
$\left| {\,\begin{array}{*{20}{c}}0&{p - q}&{p - r}\\{q - p}&0&{q - r}\\{r - p}&{r - q}&0\end{array}\,} \right| = $
A
$0$
B
$(p - q)(q - r)(r - p)$
C
$pqr$
D
$3pqr$
Solution
(a) Since determinant of a skew-symmetric matrix of odd order is zero.
Standard 12
Mathematics
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