3 and 4 .Determinants and Matrices
easy

$\left| {\,\begin{array}{*{20}{c}}0&{p - q}&{p - r}\\{q - p}&0&{q - r}\\{r - p}&{r - q}&0\end{array}\,} \right| = $

A

$0$

B

$(p - q)(q - r)(r - p)$

C

$pqr$

D

$3pqr$

Solution

(a) Since determinant of a skew-symmetric matrix of odd order is zero.

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.