$\tan 5x\tan 3x\tan 2x = $
$\tan 5x - \tan 3x - \tan 2x$
$\frac{{\sin 5x - \sin 3x - \sin 2x}}{{\cos 5x - \cos 3x - \cos 2x}}$
$0$
એકપણ નહિ.
જો $A + B + C = {180^o},$ તો $\cot \frac{A}{2} + \cot \frac{B}{2} + \cot \frac{C}{2} = . . .$
જો $\tan A = \frac{1}{2},$ તો $\tan 3A = $
$(sinx + cosecx)^2 + (cosx + secx)^2 - ( tanx + cotx)^2$ =
$4 \,\,sin5^o \,\,sin55^o \,\,sin65^o$ =
$\tan \frac{A}{2} = . . .$