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3.Trigonometrical Ratios, Functions and Identities
easy
$\tan 5x\tan 3x\tan 2x = $
A
$\tan 5x - \tan 3x - \tan 2x$
B
$\frac{{\sin 5x - \sin 3x - \sin 2x}}{{\cos 5x - \cos 3x - \cos 2x}}$
C
$0$
D
इनमें से कोई नहीं
Solution
(a) यहाँ $5x = 3x + 2x $
$\Rightarrow \tan 5x = \tan (3x + 2x)$
==> $\tan 5x = \frac{{\tan 3x + \tan 2x}}{{1 – \tan 3x\tan 2x}}$
==>$\tan 5x – \tan 5x\tan 3x\tan 2x = \tan 3x + \tan 2x$
==> $\tan 5x\tan 3x\tan 2x = \tan 5x – \tan 3x – \tan 2x$.
Standard 11
Mathematics
