$\frac{{\sin 3\theta - \cos 3\theta }}{{\sin \theta + \cos \theta }} + 1 = $
$2\sin 2\theta $
$2 cos 2\theta$
$\tan 2\theta $
$\cot 2\theta $
यदि $\tan \frac{\theta }{2} = t,$ तब $\frac{{1 - {t^2}}}{{1 + {t^2}}}$ का मान होगा
यदि $\cos x + \cos y + \cos \alpha = 0$ तथा $\sin x + \sin y + \sin \alpha = 0,$ तब $\cot \,\left( {\frac{{x + y}}{2}} \right) = $
$2\,{\sin ^2}\beta + 4\,\,\cos \,(\alpha + \beta )\,\,\sin \,\alpha \,\sin \,\beta + \cos \,2\,(\alpha + \beta ) = $
यदि $\tan \alpha = \frac{1}{7}$ तथा $\sin \beta = \frac{1}{{\sqrt {10} }}\left( {0 < \alpha ,\,\beta < \frac{\pi }{2}} \right)$, तब $2\beta $ बराबर है
${\sin ^2}\frac{\pi }{8} + {\sin ^2}\frac{{3\pi }}{8} + {\sin ^2}\frac{{5\pi }}{8} + {\sin ^2}\frac{{7\pi }}{8} = $