$\sqrt {2 + \sqrt {2 + 2\cos 4\theta } } = $
$\sqrt {2 + \sqrt {2 + 2\cos 4\theta } } = $
- A
$\cos \theta $
- B
$\sin \theta $
- C
$2\cos \theta $
- D
$2\sin \theta $
Similar Questions
$\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }} =$
$\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }} =$
- [IIT 1974]
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${\cos ^2}A{(3 - 4{\cos ^2}A)^2} + {\sin ^2}A{(3 - 4{\sin ^2}A)^2} = $
${\cos ^2}A{(3 - 4{\cos ^2}A)^2} + {\sin ^2}A{(3 - 4{\sin ^2}A)^2} = $