$1 + \cos \,{56^o} + \cos \,{58^o} - \cos {66^o} = $
$1 + \cos \,{56^o} + \cos \,{58^o} - \cos {66^o} = $
- [IIT 1964]
- A
$2\,\cos {28^o}\,\cos \,{29^o}\,\cos \,{33^o}$
- B
$4\,\cos {28^o}\,\cos \,{29^o}\,\cos \,{33^o}$
- C
$4\,\cos {28^o}\,\cos \,{29^o}\,\sin {33^o}$
- D
$2\,\cos {28^o}\,\cos \,{29^o}\,\sin \,{33^o}$
Similar Questions
જો $A + B + C = \pi ,$ તો $\frac{{\cos A}}{{\sin B\sin C}} + \frac{{\cos B}}{{\sin C\sin A}} + \frac{{\cos C}}{{\sin A\sin B}} = $
જો $A + B + C = \pi ,$ તો $\frac{{\cos A}}{{\sin B\sin C}} + \frac{{\cos B}}{{\sin C\sin A}} + \frac{{\cos C}}{{\sin A\sin B}} = $
જો $\alpha + \beta - \gamma = \pi ,$ તો ${\sin ^2}\alpha + {\sin ^2}\beta - {\sin ^2}\gamma = $
જો $\alpha + \beta - \gamma = \pi ,$ તો ${\sin ^2}\alpha + {\sin ^2}\beta - {\sin ^2}\gamma = $
- [IIT 1980]
${\rm{cosec }}A - 2\cot 2A\cos A = $
${\rm{cosec }}A - 2\cot 2A\cos A = $
ત્રિકોણ $ABC$ માટે ,$\sin A + \sin B + \sin C = . . . .$
ત્રિકોણ $ABC$ માટે ,$\sin A + \sin B + \sin C = . . . .$
જો $3\cos \theta + 4\sin \theta = 5$ અને $3\sin \theta - 4\cos \theta $ =
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