$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 $ is equal to
$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 $ is equal to
- [IIT 1966]
- [IIT 1975]
- A
$\cot 7\frac{{{1^o}}}{2}$
- B
$\sin 7\frac{{{1^o}}}{2}$
- C
$\sin \,{15^o}$
- D
$\cos \,\,{15^o}$
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