$2\,{\sin ^2}\beta + 4\,\,\cos \,(\alpha + \beta )\,\,\sin \,\alpha \,\sin \,\beta + \cos \,2\,(\alpha + \beta ) = $
$2\,{\sin ^2}\beta + 4\,\,\cos \,(\alpha + \beta )\,\,\sin \,\alpha \,\sin \,\beta + \cos \,2\,(\alpha + \beta ) = $
- [IIT 1977]
- A
$\sin \,\,2\alpha $
- B
$\cos \,\,2\beta $
- C
$\cos \,\,2\alpha $
- D
$\sin \,\,2\beta $
Similar Questions
$\cot {70^o} + 4\cos {70^o} = . . .$
$\cot {70^o} + 4\cos {70^o} = . . .$
જો $\sin x + \cos x = \frac{1}{5},$ તો $\tan 2x = . . .$
જો $\sin x + \cos x = \frac{1}{5},$ તો $\tan 2x = . . .$
$\cos \left(\frac{2 \pi}{7}\right)+\cos \left(\frac{4 \pi}{7}\right)+\cos \left(\frac{6 \pi}{7}\right)$ ની કિંમત $\dots\dots$છે.
$\cos \left(\frac{2 \pi}{7}\right)+\cos \left(\frac{4 \pi}{7}\right)+\cos \left(\frac{6 \pi}{7}\right)$ ની કિંમત $\dots\dots$છે.
- [JEE MAIN 2022]
ત્રિકોણ $ABC$ માં , ${\sin ^2}\frac{A}{2} + {\sin ^2}\frac{B}{2} + {\sin ^2}\frac{C}{2} = . . . .$
ત્રિકોણ $ABC$ માં , ${\sin ^2}\frac{A}{2} + {\sin ^2}\frac{B}{2} + {\sin ^2}\frac{C}{2} = . . . .$
સાબિત કરો કે : $\tan 4 x=\frac{4 \tan x\left(1-\tan ^{2} x\right)}{1-6 \tan ^{2} x+\tan ^{4} x}$
સાબિત કરો કે : $\tan 4 x=\frac{4 \tan x\left(1-\tan ^{2} x\right)}{1-6 \tan ^{2} x+\tan ^{4} x}$