14.Probability
normal

$P(A \cup B) = P(A \cap B)$ यदि और केवल यदि $P(A)$ और $P(B)$ के बीच सम्बन्ध हैं

A

$P(A) = P(\bar A)$

B

$P\,(A \cap B) = P(A' \cap B')$

C

$P\,(A) = P\,(B)$

D

इनमें से कोई नहीं

(IIT-1985)

Solution

(c) $P(A) = P(B)$

अत: $P(A \cup B) = P(A) + P(B) – P(A \cap B)$

या $P(A) = 2P(A) – P(A)$$ \Rightarrow P(A \cup B) = P(A \cap B).$

Standard 11
Mathematics

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