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14.Probability
easy
यदि $A, B, C$ ऐसी घटनाएँ हैं कि $P\,(A) = P\,(B) = P\,(C) = \frac{1}{4},\,P\,(AB) = P\,(CB) = 0,\,P\,(AC) = \frac{1}{8},$ तो $P\,(A + B) = $
A
$0.125$
B
$0.25$
C
$0.375$
D
$0.5$
Solution
(d) $P(A + B) = P(A) + P(B) – P(AB)$
$ = \frac{1}{4} + \frac{1}{4} – 0 = \frac{1}{2}.$
Standard 11
Mathematics