For any two statements $p$ and $q,$ the negation of the expression $p \vee ( \sim p\, \wedge \,q)$ is
$p \leftrightarrow q$
$\sim p\, \vee \,\sim q$
$\sim p\, \wedge \,\sim q$
$p\, \wedge \,q$
The converse of the statement $((\sim p) \wedge q) \Rightarrow r$ is
The statement $(p \Rightarrow q) \vee(p \Rightarrow r)$ is NOT equivalent to.
The statement $p \to ( q \to p)$ is equivalent to
Let $r \in\{p, q, \sim p, \sim q\}$ be such that the logical statement $r \vee(\sim p) \Rightarrow(p \wedge q) \vee r \quad$ is a tautology. Then ' $r$ ' is equal to
The compound statement $(\sim( P \wedge Q )) \vee((\sim P ) \wedge Q ) \Rightarrow((\sim P ) \wedge(\sim Q ))$ is equivalent to