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1.Units, Dimensions and Measurement
medium
$M{L^3}{T^{ - 1}}{Q^{ - 2}}$ એ કોનું પારિમાણિક સૂત્ર છે?
Aઅવરોઘકતા
Bવાહકતા
Cઅવરોધ
Dએક પણ નહીં
Solution
(a) Resistivity $[\rho ] = \frac{{[R]\,.\,[A]}}{{[l]}}$
${\rm{where }} [R] = [M{L^2}{T^{ – 1}}{Q^{ – 2}}]$
$\therefore $ $[\rho ] = [M{L^3}{T^{ – 1}}{Q^{ – 2}}]$
${\rm{where }} [R] = [M{L^2}{T^{ – 1}}{Q^{ – 2}}]$
$\therefore $ $[\rho ] = [M{L^3}{T^{ – 1}}{Q^{ – 2}}]$
Standard 11
Physics
