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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$10^{-3}$$M$ $NH_4OH$ ના $pOH$ નું મુલ્ય શોધો. જો $K_b$ = $10^{-5}$
A
$9$
B
$6$
C
$4$
D
$10$
Solution
$\begin{gathered}
{\text{[O}}{{\text{H}}^{\text{ – }}}] = \sqrt {{K_b} \times C} \hfill \\
= \sqrt {{{10}^{ – 5}} \times {{10}^{ – 3}}} = \sqrt {{{10}^{ – 8}}} = {10^{ – 4}} \hfill \\
\end{gathered} $
$pOH$ =$ -log [OH^{-}]$ = $- log [10^{-4}] $ = $ 4\, log\, 10 = 4$
Standard 11
Chemistry
