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6-2.Equilibrium-II (Ionic Equilibrium)
medium

$10^{-2}\, M\, HCN$ અને $[H^+]$ = $10^{-3}$ માટે વિયોજન અચણાંક નું મુલ્ય.....$\%$ માં શોધો.

A

$9$

B

$10$

C

$5$

D

$11$

Solution

${\text{[}}{{\text{H}}^ + }] = C\alpha \,\,\,\,{10^{ – 3}} = {10^{ – 2}}\alpha $

$\alpha  = \frac{{{{10}^{ – 3}}}}{{{{10}^{ – 2}}}} = {10^{ – 1}} = 0.1 = 10\% $

Standard 11
Chemistry

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