100, W ,1 ,kg ,U^{235} વિખંડનથી પેદા થાય છે. | vedclass

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Question

$P\,\, = \,\, \frac{M}{t}\,\, 	imes \,\,\frac{{{N_A}}}{{{M_\omega }}}\,\, 	imes \,\,200\,\, 	imes \,\,1.6\,\, 	imes \,\,{10^{ - 13}}\,J\,$

$\,

Vedclass · Accepted Answer

$2.5 &times;10^4$ વર્ષ

Vedclass · Answer

$P\,\, = \,\, \frac{M}{t}\,\, 	imes \,\,\frac{{{N_A}}}{{{M_\omega }}}\,\, 	imes \,\,200\,\, 	imes \,\,1.6\,\, 	imes \,\,{10^{ - 13}}\,J\,$

$\, \Rightarrow \,\,\,t\,\, = \,\,\frac{M}{P}\,\, 	imes \,\,\frac{{{N_A}}}{{{M_\omega }}}\,\, 	imes \,\,200\,\, 	imes \,\,1.6\,\, 	imes \,\,{10^{ - 13}}$

$	herefore$ $\,t\,\, = \,\,\frac{{1\,kg}}{{100\,\,W}}\,\, 	imes \,\,\frac{{6\,\, 	imes \,\,{{10}^{23}}}}{{235\,\, 	imes \,\,{{10}^{ - 3}}kg}}\,\, 	imes \,\,200\,\, 	imes \,\,1.6\,\, 	imes \,\,{10^{ - 13}}\,J\,$

$ \approx \,\,\,8.17\,\, 	imes \,\,{10^{11}}\,s\,\,\, \approx \,\,2.5\, 	imes \,\,{10^4}\,$ વર્ષ

$100\, W \,1 \,kg \,U^{235}$ વિખંડનથી પેદા થાય છે. આશરે કેટલા સમય સુધી ઊર્જા નું ઉત્પાદન ચાલુ રાખશે?

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