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$100\, W \,1 \,kg \,U^{235}$ વિખંડનથી પેદા થાય છે. આશરે કેટલા સમય સુધી ઊર્જા નું ઉત્પાદન ચાલુ રાખશે?
$2.5 ×10^4$ વર્ષ
$10^6$ સેકન્ડ
$8.6 × 10^7$ સેકન્ડ
$100 $ વર્ષ
Solution
$P\,\, = \,\, \frac{M}{t}\,\, \times \,\,\frac{{{N_A}}}{{{M_\omega }}}\,\, \times \,\,200\,\, \times \,\,1.6\,\, \times \,\,{10^{ – 13}}\,J\,$
$\, \Rightarrow \,\,\,t\,\, = \,\,\frac{M}{P}\,\, \times \,\,\frac{{{N_A}}}{{{M_\omega }}}\,\, \times \,\,200\,\, \times \,\,1.6\,\, \times \,\,{10^{ – 13}}$
$\therefore$ $\,t\,\, = \,\,\frac{{1\,kg}}{{100\,\,W}}\,\, \times \,\,\frac{{6\,\, \times \,\,{{10}^{23}}}}{{235\,\, \times \,\,{{10}^{ – 3}}kg}}\,\, \times \,\,200\,\, \times \,\,1.6\,\, \times \,\,{10^{ – 13}}\,J\,$
$ \approx \,\,\,8.17\,\, \times \,\,{10^{11}}\,s\,\,\, \approx \,\,2.5\, \times \,\,{10^4}\,$ વર્ષ
