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$a$ બાજુ વાળા ચોરસના કેન્દ્રથી ઉપર અને સમતલ $a/2$ અંતરે બિંદુવત વિદ્યુતભાર મૂકેલો છે. ચોરસ પરનું વિદ્યુત ફલક્સ ........ છે.
$\frac{q}{{{ \in _0}}}$
$\frac{q}{{\pi \,\,{ \in _0}}}$
$\frac{q}{{4\,\,{ \in _0}}}$
$\frac{q}{{6\,\,{ \in _0}}}$
Solution
We are given that a charge is placed at the centre of a square of side a at distance $a / 2$ :
Let us consider a cube that is enclosed and the square having a point charge at the centre.
A cube has six surfaces. Therefore flux is passing through six surface.
By using Gauss's law
$\Phi=\frac{ Qin ^{-}}{\epsilon_0} \quad\left\{ Q _{\text {in }}= Q _{\text {inclosed }}\right\}$
$Q _{ in }= q$
$\Phi=\frac{ q }{\epsilon_0}$
$\Phi$ is the flux electric flux passing through cube.
Step $2$: Electric flux through each side of the cube:
$\Phi=\frac{\Phi}{6}$
$\Phi=\frac{q}{6 \epsilon_0}$
