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Hindi
1. Electric Charges and Fields
normal

મુક્ત અવકાશમાં વિદ્યુત પરમિટિવિટિ નું મૂલ્ય ........ છે.

A

$9 \times  10^9\,NC^2/m^2$

B

$8.9 \times  10^{-12}\, Nm^2/C^{2}$

C

$8.9 \times  10^{-12} \,C^2/Nm^2$

D

$8.9 \times  10^9 \,C^2/Nm^2$

Solution

$\operatorname{From} F =\frac{1}{4 \pi \varepsilon_0} \frac{ q ^2}{ r ^2}$

If Force, $F=1 N$

charge, $q=1 C$

distance, $r=1 m$

Then, $q_0=\frac{q^2}{F \times 4 \pi \times r^2}$

$=\frac{(1)^2}{1 N \times 4 \times 3.14 \times(1 m )^2}$

$\varepsilon_0=8.854 \times 10^{-12} \frac{ C ^2}{ Nm ^2}$

Standard 12
Physics

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