3-1.Vectors
medium

$ABC$ એ સમબાજુ ત્રિકોણ છે. દરેક બાજુની લંબાઈ $'a'$ અને તેનું પરિકેન્દ્ર $O$ છે. તો $\overrightarrow{A B}+\overrightarrow{B C}+\overrightarrow{C A}=.......$

A

$0$

B

$1$

C

$2$

D

$3$

Solution

$\overrightarrow{A B}, \overrightarrow{B C}$ and $\overrightarrow{C A}$ form a closed triangle in the same order.

$\therefore \overrightarrow{A B}+\overrightarrow{B C}+\overrightarrow{C A}=\overrightarrow{0}$

Standard 11
Physics

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