English
Hindi
6.Permutation and Combination
easy

ત્રણ રીંગ વડે બનેલ તાળાને $10$ ભિન્ન અક્ષરો વડે બંધ કરેલ હોય, તો તેને ખોલવા માટે કેટલા અસફળ પ્રયત્નો કરી શકાય ?

A

$3^{10} - 1$

B

$9^3$

C

$^{10}p_3- 1$

D

$10^3 - 1$

Solution

The total number of ways to make ttempt to open the lock = $10 \times 10 \times 10=1000$. The number of ways to successfuly open the lock $=1 \therefore$ The number of ways to make an nsuccessful attempt to open the lock $=1000-1=$ $999$. Hence, required number of ways to make an unsuccessfuly attempt to open the lock is $999$.

Standard 11
Mathematics

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