left( {_{,4}^{47}} right) + sumlimits_{r = 1} | vedclass

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Question

$\left( {\begin{array}{*{20}{c}}
  {47} \ 
  4 
\end{array}} ight) + \sum\limits_{r = 1}^5 {\left( {\begin{array}{*{20}{c}}

Vedclass · Accepted Answer

$\left( {\begin{array}{*{20}{c}}{52}\4\end{array}} ight)$

Vedclass · Answer

$\left( {\begin{array}{*{20}{c}}
  {47} \ 
  4 
\end{array}} ight) + \sum\limits_{r = 1}^5 {\left( {\begin{array}{*{20}{c}}
  {52 - r} \ 
  3 
\end{array}} ight)} $

$ = \left( {\begin{array}{*{20}{c}}
  {51} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {50} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {49} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {48} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {47} \ 
  4 
\end{array}} ight)$

$\left( {\begin{array}{*{20}{c}}
  {51} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {50} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {49} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {48} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {48} \ 
  4 
\end{array}} ight)$

$ = \left( {\begin{array}{*{20}{c}}
  {51} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {50} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {49} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {49} \ 
  4 
\end{array}} ight)$

$\left( {\begin{array}{*{20}{c}}
  {51} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {50} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {50} \ 
  4 
\end{array}} ight)$

$ = \left( {\begin{array}{*{20}{c}}
  {51} \ 
  3 
\end{array}} ight) + \left( {\begin{array}{*{20}{c}}
  {51} \ 
  4 
\end{array}} ight) = \left( {\begin{array}{*{20}{c}}
  {52} \ 
  4 
\end{array}} ight)$

$\left( {_{\,4}^{47}} \right) + \sum\limits_{r = 1}^5 {\left( {_{\,\,\,\,3}^{52 - r}} \right)} = .........$

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જો સમિતી ઓછામાં ઓછી એક સ્ત્રી ધરાવે તો $6$ પુરૂષો અને $4$ સ્ત્રીઓ પૈકી $5$ સભ્યોની સમિતી કેટલી રીતે બનાવી શકાય ?

$\left( {\begin{array}{{20}{c}}n\\{r + 1}\end{array}} \right) + 2\left( {\begin{array}{{20}{c}}n\\r\end{array}} \right) + \left( {\begin{array}{*{20}{c}}n\\{r - 1}\end{array}} \right) = .......$

જો ${ }^{2n } C _3:{ }^{n } C _3=10: 1$,હોય,તો ગુણોત્તર $\left(n^2+3 n\right):\left(n^2-3 n+4\right)$ $...........$ છે.

$\left( {_{\,4}^{47}} \right) + \sum\limits_{r = 1}^5 {\left( {_{\,\,\,\,3}^{52 - r}} \right)} = .........$

Similar Questions

જો સમિતી ઓછામાં ઓછી એક સ્ત્રી ધરાવે તો $6$ પુરૂષો અને $4$ સ્ત્રીઓ પૈકી $5$ સભ્યોની સમિતી કેટલી રીતે બનાવી શકાય ?

$\left( {\begin{array}{*{20}{c}}n\\{r + 1}\end{array}} \right) + 2\left( {\begin{array}{*{20}{c}}n\\r\end{array}} \right) + \left( {\begin{array}{*{20}{c}}n\\{r - 1}\end{array}} \right) = .......$

જો ${ }^{2n } C _3:{ }^{n } C _3=10: 1$,હોય,તો ગુણોત્તર $\left(n^2+3 n\right):\left(n^2-3 n+4\right)$ $...........$ છે.

$\left( {\begin{array}{{20}{c}}n\\{r + 1}\end{array}} \right) + 2\left( {\begin{array}{{20}{c}}n\\r\end{array}} \right) + \left( {\begin{array}{*{20}{c}}n\\{r - 1}\end{array}} \right) = .......$