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4-2.Quadratic Equations and Inequations
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જો $x = \sqrt {6 + \sqrt {6 + \sqrt {6 + ....{\rm{to}}\,\,\infty } } ,} $ તો,.........

A

$x$ એ અસંમેય સંખ્યા છે.

B

$2 < x < 3$

C

$x = 3$

D

એકપણ નહી.

Solution

$\,x = \sqrt {6 + x} ,$$x > 0\,\, $

$\Rightarrow {x^2} = 6 + x,x > 0$

$ \Rightarrow {x^2} – x – 6 = 0,\,x > 0$ 

$ \Rightarrow x = 3,x > 0$

Standard 11
Mathematics

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