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4-2.Quadratic Equations and Inequations
hard
$\sin ^2 x+\left(2+2 x-x^2\right) \sin x-3(x-1)^2=0,-\pi \leq x \leq \pi$ ના ઉકેલો ની સંખ્યા ............ છે.
A
$6$
B
$7$
C
$2$
D
$4$
(JEE MAIN-2024)
Solution
$ \sin ^2 x-\left(x^2-2 x-2\right) \sin x-3(x-1)^2=0 $
$ \left.\sin ^2 x-(x-1)^2\right) \sin x-3(x-1)^2=0$
$Image$
$ \sin x=-3( reject) or (x-1)^2 $
$ \sin x=(x-1)^2$
$Image$
Standard 11
Mathematics
