$n\,\,(U)\, = \left( \begin{gathered}
  52 \hfill \\
  13 \hfill \\ 
\end{gathered}  \right)$

ધારો કે ઘટના પસંદ થયેલ $13$ પત્તાંમાં  $4$ પત્તાં રાજાના હોય

$\therefore \,\,n\,(A)\, = \,\left( \begin{gathered}
  4 \hfill \\
  4 \hfill \\ 
\end{gathered}  \right)\left( \begin{gathered}
  48 \hfill \\
  \,\,9 \hfill \\ 
\end{gathered}  \right) = \,\left( \begin{gathered}
  48 \hfill \\
  \,\,9 \hfill \\ 
\end{gathered}  \right)\,\,$

$\therefore \,\,\,\,P(A)\, = \,\frac{{n(A)}}{{n(U)}}\, = \,\frac{{\left( \begin{gathered}
  48 \hfill \\
  \,\,9 \hfill \\ 
\end{gathered}  \right)}}{{\left( \begin{gathered}
  52 \hfill \\
  13 \hfill \\ 
\end{gathered}  \right)}}$

$ = \,\frac{{48\,!}}{{39\,!\,9\,!}} \times \frac{{39\,!\,13\,!}}{{52\,!}} = \,\frac{{48\,!\,13.12.11.10.9\,!}}{{9!52.51.50.49.48!}} = \,\frac{{11}}{{4165}}$