જો ઊર્જા E = G^p h^q c^r છે જ્યાં G | vedclass

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Question

$E\,\, = \,{G^p}{h^q}{C^r}\,$

$\left[ {{M^1}{L^2}{T^{ - 2}}} \right]\,\, = \,\,{\left[ {{M^{ - 1}}{L^3}{T^{ - 2}}} \right]^p}{\left[ {{M^1}{L^2}{T^

Vedclass · Accepted Answer

$ - \frac{1}{2},\frac{1}{2}\,\, $અને $ \,\frac{5}{2}$

Vedclass · Answer

$E\,\, = \,{G^p}{h^q}{C^r}\,$

$\left[ {{M^1}{L^2}{T^{ - 2}}} \right]\,\, = \,\,{\left[ {{M^{ - 1}}{L^3}{T^{ - 2}}} \right]^p}{\left[ {{M^1}{L^2}{T^{ - 1}}} \right]^q}\,\,{\left[ {{L^1}{T^{ - 1}}} \right]^r}$

$m$ નો પાવર $ \Rightarrow \,\,1\, =  - p\,\, + \;\;q\,\, + \;\,0\,\,\,........\left( i \right)$

$L$ નો પાવર $\, \Rightarrow \,\,2\,\, = \,\,3p\,\, + \,\,2q\,\, + \,\,r\,\,...........\left( {ii} \right)$

$T$ નો પાવર  $ \Rightarrow  - 2\,\, =  - 2P\,\, - \,\,q\,\, - \,\,r\,\,\,\,.............\left( {iii} \right)$

આ સમીકરણ ને ઉકેલવા $\,\,p\,\, = \,\, - \frac{1}{2},\,\,q\,\, = \,\,\frac{1}{2}\,\,r\,\, = \,\,\frac{5}{2}$

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