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11.Dual Nature of Radiation and matter
easy

$\lambda = 4000\ \mathring A $ ની તંરગ લંબાઈના ફોટોનની ઊર્જા = ..….$eV.$

A$4$
B$3.1$
C$4.9$
D$5.1$

Solution

$E\,\, = \,\, \frac{{12400eV}}{{4000}}\,\,\, = \,\,\,3.1\,\,\,eV$
Standard 12
Physics

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