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9.Straight Line
normal
ત્રિકોણ $PQS$ અને $PQR$ ના ક્ષેત્રનો ગુણોત્તર . . . . .
A
$1\,\,\,\,:\,\sqrt 2 $
B
$1 : 2$
C
$1 : 4$
D
$1 : 8$
Solution
Coordinates of $P$ and $Q$ are $(1,+2 \sqrt{2})$ and $(1,-2 \sqrt{2})$.
Area of $\triangle P Q R=\frac{1}{2} \cdot 4 \sqrt{2} \cdot 8=16 \sqrt{2}$
Area of $\triangle P Q S=\frac{1}{2} \cdot 4 \sqrt{2} \cdot 2=4 \sqrt{2}$
Ratio of area of triangle PQS and PQR is $1: 4$.
Standard 11
Mathematics