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5.Work, Energy, Power and Collision
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પદાર્થની સ્થિતિઊર્જા $U = 8{x^2} - 4x + 400 \, J$.
A
$x = 25\,m$
B
$x = 0.25\,m$
C
$x = 0.025\,m$
D
$x = 2.5\,m$
Solution
$F = – \frac{{dU}}{{dx}} = – \frac{d}{{dx}}(8{x^2} – 4x + 400)$
$F = – \frac{{dU}}{{dx}} = 0$ ==> $16x – 4 = 0$
==>$x = 4/16$
$x = 0.25\,m$.
Standard 11
Physics
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