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5.Work, Energy, Power and Collision
normal

પદાર્થની સ્થિતિઊર્જા $U = 8{x^2} - 4x + 400 \, J$.

A

$x = 25\,m$

B

$x = 0.25\,m$

C

$x = 0.025\,m$

D

$x = 2.5\,m$

Solution

$F = – \frac{{dU}}{{dx}} = – \frac{d}{{dx}}(8{x^2} – 4x + 400)$

$F = – \frac{{dU}}{{dx}} = 0$ ==> $16x – 4 = 0$

==>$x = 4/16$

$x = 0.25\,m$.

Standard 11
Physics

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