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12.Kinetic Theory of Gases
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$20\,\, lit$ ${H_2}$ ની ગતિઊર્જા $1.5 \times {10^5}\,J$ છે.તો પાત્ર પર લાગતું દબાણ
A
$2 \times {10^6}\,N/{m^2}$
B
$3 \times {10^6}\,N/{m^2}$
C
$4 \times {10^6}\,N/{m^2}$
D
$5 \times {10^6}\,N/{m^2}$
Solution
ગતિઊર્જા $E = 1.5 \times {10^5}\,J$, $V = 20\, litre$
= $20 \times {10^{ – 3}}{m^3}$
દબાણ $ = \frac{2}{3}\frac{E}{V}$
$ = \frac{2}{3}\left( {\frac{{1.5 \times {{10}^5}}}{{20 \times {{10}^{ – 3}}}}} \right) = 5 \times {10^6}\,N/{m^2}$.
Standard 11
Physics
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