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12.Kinetic Theory of Gases
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પહાડની ઉપર અને નીચે ઘનતાનો ગુણોતર
A
$75/76$
B
$70/76$
C
$76/75$
D
$76/70 $
Solution
$\frac{{{P_1}}}{{{\rho _1}{T_1}}} = \frac{{{P_2}}}{{{\rho _2}{T_2}}} = $constant $\frac{{{\rho _1}}}{{{\rho _2}}} = \frac{{{P_1}}}{{{P_2}}} \times \frac{{{T_2}}}{{{T_1}}}$
$\frac{{{\rho _{{\rm{Top}}}}}}{{{\rho _{{\rm{Bottom}}}}}} = \frac{{{P_{{\rm{Top}}}}}}{{{P_{{\rm{Bottom}}}}}} \times \frac{{{T_{{\rm{Bottom}}}}}}{{{T_{{\rm{Top}}}}}} = \frac{{70}}{{76}} \times \frac{{300}}{{280}} = \frac{{75}}{{76}}$
Standard 11
Physics
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