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10-2.Transmission of Heat
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Six identical conducting rods are joined as shown in figure. Points $A$ and $D$ are maintained at temperature of $200^o C$ and $20^o C$ respectively. The temperature of junction $B$ will be ....... $^oC$ 
A$120$
B$100$
C$140$
D$80$
Solution

$\Rightarrow \theta = \frac{{R \times 20 + 2R \times 200}}{{R + 2R}} = \frac{{420}}{3} = {140^o}C.$
Standard 11
Physics
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