10-2.Transmission of Heat
medium

Six identical conducting rods are joined as shown in figure. Points $A$ and $D$ are maintained at temperature of $200^o C$ and $20^o C$ respectively. The temperature of junction $B$ will be  ....... $^oC$ 

A$120$
B$100$
C$140$
D$80$

Solution

સંપર્ક સપાટીનું તાપમાન $\theta = \frac{{{R_1}{\theta _2} + {R_2}{\theta _1}}}{{{R_1} + {R_2}}}$
$\Rightarrow \theta = \frac{{R \times 20 + 2R \times 200}}{{R + 2R}} = \frac{{420}}{3} = {140^o}C.$
Standard 11
Physics

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