English
Hindi
8.Electromagnetic waves
medium

વિધુતચુંબકીય તરંગ માટે વિધુતક્ષેત્ર ${E_x} = 36\sin (1.20 \times {10^7}z - 3.6 \times {10^{15}}t)\,V/m$ હોય તો વિધુતક્ષેત્રની તીવ્રતા કેટલા ....$W/{m^2}$ થાય?

A

$0.86$

B

$1.72$

C

$3.44$

D

$6.88$

Solution

${I_{av}} = \frac{{c{\varepsilon _0}E_0^2}}{2} = \frac{{3 \times {{10}^8} \times 8.85 \times {{10}^{ – 15}} \times {{36}^2}}}{2}$$ = 1.72\;W/{m^2}$

Standard 12
Physics

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