$\sum\limits_{r = 1}^{89} {{{\log }_3}(\tan \,\,{r^o})} = $
$\sum\limits_{r = 1}^{89} {{{\log }_3}(\tan \,\,{r^o})} = $
- A
$3$
- B
$1$
- C
$2$
- D
$0$
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- [IIT 1990]
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