Gujarati
Basic of Logarithms
medium

The value of $\left(\left(\log _2 9\right)^2\right)^{\frac{1}{\log _2\left(\log _2 9\right)}} \times(\sqrt{7})^{\frac{1}{\log _4 7}}$ is. . . . . . .

A

$5$

B

$8$

C

$9$

D

$10$

(IIT-2018)

Solution

$=\left(\log _2 9\right)^{\log _{\log _2 9} 2^2} \times 7^{\log _7 2}$  $=4 \times 2=8$

Standard 11
Mathematics

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