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Basic of Logarithms
medium
The value of $\left(\left(\log _2 9\right)^2\right)^{\frac{1}{\log _2\left(\log _2 9\right)}} \times(\sqrt{7})^{\frac{1}{\log _4 7}}$ is. . . . . . .
A
$5$
B
$8$
C
$9$
D
$10$
(IIT-2018)
Solution
$=\left(\log _2 9\right)^{\log _{\log _2 9} 2^2} \times 7^{\log _7 2}$ $=4 \times 2=8$
Standard 11
Mathematics