The value of ${(0.05)^{{{\log }_{_{\sqrt {20} }}}(0.1 + 0.01 + 0.001 + ......)}}$ is
$81$
${1 \over {81}}$
$20$
$0.05$
The set of real values of $x$ satisfying ${\log _{1/2}}({x^2} - 6x + 12) \ge - 2$ is
If ${a^x} = b,{b^y} = c,{c^z} = a,$ then value of $xyz$ is
If $A = {\log _2}{\log _2}{\log _4}256 + 2{\log _{\sqrt 2 \,}}\,2,$ then $A$ is equal to
If ${\log _7}2 = m,$ then ${\log _{49}}28$ is equal to
Solution set of inequality ${\log _{10}}({x^2} - 2x - 2) \le 0$ is