The value of ${(0.05)^{{{\log }_{_{\sqrt {20} }}}(0.1 + 0.01 + 0.001 + ......)}}$ is
$81$
${1 \over {81}}$
$20$
$0.05$
The value of $\sqrt {(\log _{0.5}^24)} $ is
If ${a^2} + 4{b^2} = 12ab,$ then $\log (a + 2b)$ is
If ${1 \over {{{\log }_3}\pi }} + {1 \over {{{\log }_4}\pi }} > x,$ then $x$ be
If $a = {\log _{24}}12,\,b = {\log _{36}}24$ and $c = {\log _{48}}36,$ then $1+abc$ is equal to
If ${\log _5}a.{\log _a}x = 2,$then $x$ is equal to