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5.Work, Energy, Power and Collision
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$F = 2x^2 - 3x - 2$. Choose correct option
A
$x = - 1/2$ is position of stable equilibrium
B
$x = 2$ is position of stable equilibrium
C
$x = - 1/2$ is position of unstable equilibrium
D
$x= 2$ is position of neutral equilibrium
Solution
$F=2 x^{2}-3 x-2=0$
$2 x^{2}-4 x+x-2=0$
$2 x(x-2)+1(x-2)=0$
$(x-2)(2 x+1)=0$
$d F=(4 x-3) d x$
$x=2 \Rightarrow \quad d F=(4 x 2-3) d x \quad \Rightarrow \quad d f=5 d x$
$x=-1 / 2 \quad d f \quad\left(4 x\frac{-1}{2}-1\right) d x=-5d x$
$x=-1 / 2$
Standard 11
Physics
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