$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ is
equivalent to $p \wedge q$
Tautology
Fallacy
Neither tautology nor fallacy
Let $r \in\{p, q, \sim p, \sim q\}$ be such that the logical statement $r \vee(\sim p) \Rightarrow(p \wedge q) \vee r \quad$ is a tautology. Then ' $r$ ' is equal to
Which of the following is always true
If $p, q, r$ are simple propositions with truth values $T, F, T$, then the truth value of $(\sim p \vee q)\; \wedge \sim r \Rightarrow p$ is
Which one of the following Boolean expressions is a tautology?
The statement $p → (p \leftrightarrow q)$ is logically equivalent to :-