$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ is
equivalent to $p \wedge q$
Tautology
Fallacy
Neither tautology nor fallacy
If the truth value of the statement $p \to \left( { \sim q \vee r} \right)$ is false $(F)$, then the truth values of the statement $p, q, r$ are respectively
Let $r \in\{p, q, \sim p, \sim q\}$ be such that the logical statement $r \vee(\sim p) \Rightarrow(p \wedge q) \vee r \quad$ is a tautology. Then ' $r$ ' is equal to
Which one of the following is a tautology ?
Which one of the following, statements is not a tautology
The false statement in the following is