A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random, then probability

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14.Probability

easy

A bag contains $6$ red, $4$ white and $8$ blue balls. If three balls are drawn at random, then the probability that $2$ are white and $1$ is red, is

A

$\frac{5}{{204}}$

B

$\frac{7}{{102}}$

C

$\frac{3}{{68}}$

D

$\frac{1}{{13}}$

Solution

(c) Required probability $ = \frac{{{}^4{C_2} \times {}^6{C_1}}}{{{}^{18}{C_3}}} = \frac{3}{{68}}.$

Standard 11

Mathematics

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