A Body moves $6\, m$ north. $8 \,m$ east and $10\;m$ vertically upwards, what is its resultant displacement from initial position
$10\sqrt 2 m$
$10m$
$\frac{{10}}{{\sqrt 2 }}\,m$
$10 \times 2\,m$
A particle moves along $x$-axis as $x=4(t-2)+a(t-2)^2$. Which of the following statements is true?
A car is moving with velocity $V$. If stop after applying break at a distance of $20\; m$. If velocity of car is doubled, then how much distance it will cover (travel) after applying break
A body starts from rest from the origin with an acceleration of $6\,m/{s^2}$ along the $x-$axis and $8\,m/{s^2}$ along the $y-$axis. Its distance from the origin after $4 \,seconds$ will be........$m$
The velocity- displacement graph of a particle is shown in figure.
$(a)$ Write the relation between $v$ and $x$.
$(b)$ Obtain the relation between acceleration and displacement and plot it.
The velocity-time graphs of a car and a scooter are shown in the figure. $(i)$ the difference between the distance travelled by the car and the scooter in $15\, s$ and $(ii)$ the time at which the car will catch up with the scooter are, respectively