The position of a particle moving along $x$-axis given by $x=\left(-2 t^3+3 t^2+5\right) m$. The acceleration of particle at the instant its velocity becomes zero is ....... $m / s ^2$
What do you mean by term relative velocity ?
A particle starts from the origin at $\mathrm{t}=0$ with an initial velocity of $3.0 \hat{\mathrm{i}} \;\mathrm{m} / \mathrm{s}$ and moves in the $x-y$ plane with a constant acceleration $(6.0 \hat{\mathrm{i}}+4.0 \hat{\mathrm{j}}) \;\mathrm{m} / \mathrm{s}^{2} .$ The $\mathrm{x}$ -coordinate of the particle at the instant when its $y-$coordinate is $32\;\mathrm{m}$ is $D$ meters. The value of $D$ is
A particle moves along a parabolic path $y=9 x^2$ in such a way that the $x$ component of velocity remains constant and has a value $\frac{1}{3}\,m / s$. The acceleration of the particle is $.......m / s ^2$
What can be the angle between velocity and acceleration for the motion on a straight line ? Explain with example.