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3-2.Motion in Plane
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A body starts from rest from the origin with an acceleration of $6\,m/{s^2}$ along the $x-$axis and $8\,m/{s^2}$ along the $y-$axis. Its distance from the origin after $4 \,seconds$ will be........$m$
A$56$
B$64 $
C$80$
D$128$
Solution
(c) ${S_x} = {u_x}t + \frac{1}{2}{a_x}{t^2} \Rightarrow {S_x} = \frac{1}{2} \times 6 \times 16 = 48\;m$
${S_y} = {u_y}t + \frac{1}{2}{a_y}{t^2} \Rightarrow {S_y} = \frac{1}{2} \times 8 \times 16 = 64\;m$
$S = \sqrt {S_x^2 + S_y^2} = 80\,m$
${S_y} = {u_y}t + \frac{1}{2}{a_y}{t^2} \Rightarrow {S_y} = \frac{1}{2} \times 8 \times 16 = 64\;m$
$S = \sqrt {S_x^2 + S_y^2} = 80\,m$
Standard 11
Physics
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