A bullet of mass 50 mathrm{~g} is fired with | vedclass

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Question

$\mathrm{K}_{\mathrm{i}} =\frac{1}{2} \mathrm{~m}(100)^2$

$\mathrm{~K}_{\mathrm{f}} =\frac{1}{2} \mathrm{~m}(40)^2$

$\% 	ext { loss }=\frac{\left|\

Vedclass · Accepted Answer

$84 \%$

Vedclass · Answer

$\mathrm{K}_{\mathrm{i}} =\frac{1}{2} \mathrm{~m}(100)^2$

$\mathrm{~K}_{\mathrm{f}} =\frac{1}{2} \mathrm{~m}(40)^2$

$\% 	ext { loss }=\frac{\left|\mathrm{K}_{\mathrm{f}}-\mathrm{K}_{\mathrm{i}}ight|}{\mathrm{K}_{\mathrm{i}}} 	imes 100$

$=\frac{\left|\frac{1}{2} \mathrm{~m}(40)^2-\frac{1}{2} \mathrm{~m}(100)^2ight|}{\frac{1}{2} \mathrm{~m}(100)^2} 	imes 100$

$=\frac{|1600-100 	imes 100|}{100}=84 \%$

A bullet of mass $50 \mathrm{~g}$ is fired with a speed $100 \mathrm{~m} / \mathrm{s}$ on a plywood and emerges with $40 \mathrm{~m} / \mathrm{s}$. The percentage loss of kinetic energy is :