1. Electric Charges and Fields
medium

વિદ્યુતભાર $q$ ને સમાન વિદ્યુતભાર ધરાવતા બે $Q$ વિદ્યુતભારને જોડતી રેખાની મધ્યમાં મૂકવામાં આવે છે. જો ત્રણ વિદ્યુતભારનું તંત્ર સમતોલનમાં રહે જો $q=$ 

A

$ - \frac{Q}{2}$

B

$ - \frac{Q}{4}$

C

$ + \frac{Q}{4}$

D

$ + \frac{Q}{2}$

(AIEEE-2002) (IIT-1987) (AIPMT-1995) (AIIMS-2017)

Solution

(b) Suppose in the following figure, equilibrium of charge $B$ is considered. Hence for it's equilibrium $|{F_A}|\, = \,|{F_C}|$
$==>$ $\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{4{x^2}}} = $$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{qQ}}{{{x^2}}}$ $==>$ $q = \frac{{ – \,Q}}{4}$

Short Trick : For such type of problem the magnitude of middle charge can be determined if either of the extreme charge is in equilibrium by using the following formula.
If charge $A$ is in equilibrium then $q$ $= -$ ${Q_B}\,{\left( {\frac{{{x_1}}}{x}} \right)^2}$
If charge $B $ is in equilibrium then $q = – {Q_A}\,\,{\left( {\frac{{{x_2}}}{x}} \right)^2}$
If the whole system is in equilibrium then use either of the above formula.

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.