A circle passes through the origin and has its centre on $y = x$. If it cuts ${x^2} + {y^2} - 4x - 6y + 10 = 0$ orthogonally, then the equation of the circle is
A circle passes through the origin and has its centre on $y = x$. If it cuts ${x^2} + {y^2} - 4x - 6y + 10 = 0$ orthogonally, then the equation of the circle is
- A
${x^2} + {y^2} - x - y = 0$
- B
${x^2} + {y^2} - 6x - 4y = 0$
- C
${x^2} + {y^2} - 2x - 2y = 0$
- D
${x^2} + {y^2} + 2x + 2y = 0$
Similar Questions
The value of $\lambda $, for which the circle ${x^2} + {y^2} + 2\lambda x + 6y + 1 = 0$, intersects the circle ${x^2} + {y^2} + 4x + 2y = 0$ orthogonally is
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- [JEE MAIN 2014]
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