If the circles ${x^2} + {y^2} = {a^2}$and ${x^2} + {y^2} - 2gx + {g^2} - {b^2} = 0$ touch each other externally, then
If the circles ${x^2} + {y^2} = {a^2}$and ${x^2} + {y^2} - 2gx + {g^2} - {b^2} = 0$ touch each other externally, then
- A
$g = ab$
- B
${g^2} = {a^2} + {b^2}$
- C
${g^2} = ab$
- D
$g = a + b$
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