A closed organ pipe has length L , air in it is vibrating in third overtone with maximum amplitude &

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14.Waves and Sound

normal

A closed organ pipe has length $L$ , the air in it is vibrating in third overtone with maximum amplitude $'a'$ . The amplitude at distance $\frac {L}{7}$ from closed end of the pipe is

$0$

$a$

$\frac {a}{2}$

none

Solution

$L=\frac{7 \lambda}{4}$

$\Rightarrow \lambda=\frac{4 \mathrm{L}}{7} \Rightarrow \mathrm{K}=\frac{2 \pi}{\lambda} \Rightarrow \frac{2 \pi}{4 \mathrm{L}} \times 7=\frac{7 \pi}{2 \mathrm{L}}$

$A_{x}=a \sin K x=\operatorname{asin}\left(\frac{7 \pi}{2 L}\right)\left(\frac{L}{7}\right)=a$

Standard 11

Physics

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A closed organ pipe has length $L$ , the air in it is vibrating in third overtone with maximum amplitude $'a'$ . The amplitude at distance $\frac {L}{7}$ from closed end of the pipe is

Solution

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