A coin is tossed. If it shows head, we draw a ball from a bag consisting of $3$ blue and $4$ white balls; if it shows tail we throw a die. Describe the sample space of this experiment.
Let us denote blue balls by $B _{1}, \,B _{2},\,B _{3}$ and the white balls by $W _{1},\,W _{2}, \,W _{3}, \,W _{4}$.
Then a sample space of the experiment is
$S =\{ HB _{1}, \,HB _{2},\, HB _{3}, \,HW _{1}, \,HW _{2}$, $HW _{3}, \,HW _{4}$ , $T1,\, T 2,\, T 3$, $T 4,\, T 5,\, T 6\}$
Here $HB_i$ means head on the coin and ball $B_i$ is drawn, $HW_i$ means head on the coin and ball $W _{i}$ is drawn. Similarly, $Ti$ means tail on the coin and the number $i$ on the die.
Let $M$ be the maximum value of the product of two positive integers when their sum is $66$. Let the sample space $S=\left\{x \in Z: x(66-x) \geq \frac{5}{9} M\right\}$ and the event $A=\{ x \in S : x$ is a multiple of $3$ $\}$. Then $P ( A )$ is equal to
The probability of getting head and tail alternately in three throws of a coin (or a throw of three coins), is
A box contains $6$ nails and $10$ nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, what is the probability that it is rusted or is a nail
Two coins are tossed. Let $A$ be the event that the first coin shows head and $B$ be the event that the second coin shows a tail. Two events $A$ and $B$ are
A card is drawn randomly from a pack of playing cards. Then the probability that it is neither ace nor king, is