A die is thrown, find the probability of following events: A number less than or equal to one will appear,

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The sample space of the given experiment is given by 

$S=\{1,2,3,4,5,6\}$

Let $C$ be the event of the occurrence of a number less than or equal to one.

Accordingly, $C\{1\}$

$\therefore P(C)=\frac{\text { Number of outcomes favourable to } C}{\text { Total number of possible outcomes }}=\frac{n(C)}{n(S)}=\frac{1}{6}$

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