A die is thrown, find the probability of following events: A number less than or equal to one will appear,
A die is thrown, find the probability of following events: A number less than or equal to one will appear,
The sample space of the given experiment is given by
$S=\{1,2,3,4,5,6\}$
Let $C$ be the event of the occurrence of a number less than or equal to one.
Accordingly, $C\{1\}$
$\therefore P(C)=\frac{\text { Number of outcomes favourable to } C}{\text { Total number of possible outcomes }}=\frac{n(C)}{n(S)}=\frac{1}{6}$
Similar Questions
Two dice are thrown. The events $A,\, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
State true or false $:$ (give reason for your answer)
Statement : $A=B^{\prime}$
Two dice are thrown. The events $A,\, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
State true or false $:$ (give reason for your answer)
Statement : $A=B^{\prime}$
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- [KVPY 2021]