Gujarati
14.Probability
medium

A committee consists of $9$ experts taken from three institutions $A, B$ and $C$, of which $2$ are from $A, 3$ from $B$ and $4$ from $C$. If three experts resign, then the probability that they belong to different institutions is

A

$\frac{1}{{729}}$

B

$\frac{1}{{24}}$

C

$\frac{1}{{21}}$

D

$\frac{2}{7}$

Solution

(d) Required probability $ = \frac{{{}^2{C_1} \times {}^3{C_1} \times {}^4{C_1}}}{{{}^9{C_3}}} $

$= \frac{{2 \times 3 \times 4}}{{\left( {\frac{{9 \times 8 \times 7}}{{3 \times 2}}} \right)}} = \frac{2}{7}$.

Standard 11
Mathematics

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